x^2-x-6=(x-2)(x+3)

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Solution for x^2-x-6=(x-2)(x+3) equation: 



x^2-x-6=(x-2)(x+3)

We move all terms to the left:

x^2-x-6-((x-2)(x+3))=0

We add all the numbers together, and all the variables

x^2-1x-((x-2)(x+3))-6=0

We multiply parentheses ..

x^2-((+x^2+3x-2x-6))-1x-6=0



We calculate terms in parentheses: -((+x^2+3x-2x-6)), so:

(+x^2+3x-2x-6)

We get rid of parentheses

x^2+3x-2x-6

We add all the numbers together, and all the variables

x^2+x-6

Back to the equation:

-(x^2+x-6)



We add all the numbers together, and all the variables

x^2-1x-(x^2+x-6)-6=0

We get rid of parentheses

x^2-x^2-1x-x+6-6=0

We add all the numbers together, and all the variables

-2x=0

x=0/-2

x=0

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